We started the day with working on
circuit problem here is a picture:
 | |
|
We then talked about reduced row echelon
function, rref and we can rewrite matrices in that form.
We
then did an example of a material balances desalination unit. Here is a
picture:
 | |
|
We
then move onto a Force on a Statically Determinate Truss example. Here is
picture:
 | |
|
Lastly
we finish the day with special types of matrices like pascal and magic.
Conclusion:
Solving
linear algebra systems is easy with matlab. However using which type on method
is important, like ref, rref, or other forms like the first example tied in
class.
%%HMWK 11
%hmwk 11-1
doublea = 5 - 3i %double complex, 16
bytes
singlea = single(5 - 3i)
%Single complex, 8 bytes
k1 = doublea^100 %double complex
raise 100 power
k2 = singlea^100 %single comples
raise 100 power
% k1 returns intergers vaules of
double complex
% k2 returns -inf and +inf in single
complex
% the reason being the scope of single
cant handle 100 power byte "weight"
%hmwk 11-2
char(85) %one element
num2str(8)
char(56)
char(53)
%hmwk 11-3
mess = input('words','s') %message
input
encode = char(mess+11) %encode
message
decode = char(encode-11) %decode
message
%hm11-4
k = 1;
response = menu('Would you like to
enter planetary data?','yes','no');
while response==1
disp('Remember to enter strings in
single quotes')
planetary(k).name = input('Enter a
planet names','s');
planetary(k).mass = input('Enter the
mass in multiples of earth''s mass: ');
planetary(k).year = input('Enter the
length of the planetary year in Earth years: ');
planetary(k).velocity = input('Enter
the mean orbital velocity in km/sec: ');
planetary(k)
increment = menu('Was the data
correct?','Yes','No');
switch increment
case 1
increment = 1;
case 2
increment = 0;
end
k = k+increment;
response = menu('Would you like to
enter more planetary data?','yes','no');
end
plan2 = {planetary.name;
planetary.mass; planetary.year; planetary.velocity}
oo = struct2table(planetary) %struct
table command
%hmwk 11-5
metal = {'Aluminum' ,'Copper ','Iron
','Molybdenum ','Cobalt ','Vanadium '} %metal names
sy = ['AL', 'Cu', 'Fe', 'Mo', 'Co',
'V'] %element symbolys
atomicn = int8([13 29 26 42 27 23])
%atomic number of elements
atomicw = [26.98 63.55 55.85 95.94
58.93 50.94] %atomic weight of elements
den = single([2.71 8.94 7.87 10.22
8.9 6.0]) %density of each element g/cm
ty =
['FCC','FCC','BCC','BCC','HCP','BCC'] %type of structre per element
super = {metal sy atomicn atomicw
den ty} %super cell of 6 different arrays
cell2table(super)
sup1 = [super{1}(4) super{4}(4)
super{6}(10:12)] %cell sup1 is forth deep in super cell
sup2 = [super{1}]' %names of
elements in metal cell
sup3 =
sum(super{4}/length(super{4})) %average atomic weight of forth column
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